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tan 30° = 15/d, so d = 15√3 m.
Distance = 12 m. Total height = 12√3 m. Flagstaff height = 12√3 − 12 = 12(√3 − 1) m.
If building height is h, then h tan 45°/tan 30° gives h = 8/(√3 − 1) = 4(√3 + 1) m.
Height = 10 tan 60° = 10√3 m.
Let the nearer distance be x. Then h = x and h = (x + 20)/√3. Thus x√3 = x + 20, giving h = 10(√3 + 1) m.
Let the nearer distance be x. Then h = x√3 and h = (x + 10)/√3. Solving gives x = 5/√3 and h = 5√3 m.
tan 45° = 18/d, so d = 18 m.
Height = 20√3 tan 30° = 20 m.
tan 60° = 30/d, so d = 10√3 m.
Height difference = 30 tan 30° = 10√3 m.
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